• typedef struct {
        bool a: 1;
        bool b: 1;
        bool c: 1;
        bool d: 1;
        bool e: 1;
        bool f: 1;
        bool g: 1;
        bool h: 1;
    } __attribute__((__packed__)) not_if_you_have_enough_booleans_t;
    
    • @h4x0r@lemmy.dbzer0.com
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      1319 hours ago

      This was gonna be my response to OP so I’ll offer an alternative approach instead:

      typedef enum flags_e : unsigned char {
        F_1 = (1 << 0),
        F_2 = (1 << 1),
        F_3 = (1 << 2),
        F_4 = (1 << 3),
        F_5 = (1 << 4),
        F_6 = (1 << 5),
        F_7 = (1 << 6),
        F_8 = (1 << 7),
      } Flags;
      
      int main(void) {
        Flags f = F_1 | F_3 | F_5;
        if (f & F_1 && f & F_3) {
          // do F_1 and F_3 stuff
        }
      }
      
      • @anotherandrew@lemmy.mixdown.ca
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        1
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        7 hours ago

        Why not if (f & (F_1 | F_3)) {? I use this all the time in embedded code.

        edit: never mind; you’re checking for both flags. I’d probably use (f & (F_1 | F_3)) == (F_1 | F_3) but that’s not much different than what you wrote.

    • @xthexder@l.sw0.com
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      1 day ago

      Or just std::bitset<8> for C++. Bit fields are neat though, it can store weird stuff like a 3 bit integer, packed next to booleans

      • Sonotsugipaa
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        10
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        1 day ago

        That’s only for C++, as far as I can tell that struct is valid C